What Is The Least Number Which When Divided By The Numbers 3 5 6 8 10 And 12 Leaves In Each

What Is The Least Number Which When Divided By The Numbers 3, 5, 6, 8, 10 And 12 Leaves In Each ...

What Is The Least Number Which When Divided By The Numbers 3, 5, 6, 8, 10 And 12 Leaves In Each ... To solve the problem, we need to find the least number that satisfies two conditions: 1. when divided by 3, 5, 6, 8, 10, and 12, it leaves a remainder of 2. 2. when divided by 13, it leaves no remainder. step 1: find the lcm of the numbers 3, 5, 6, 8, 10, and 12. Note: question asked that the least number there can be more than one number that can be divisible by numbers 3, 5, 6, 8, 10 and 12 and leaves the remainder 2. so students should be aware of that.

What Is The Least Number Which When Divided By 5, 6, 7 And 8 Leaves A Remainder 3, But When ...

What Is The Least Number Which When Divided By 5, 6, 7 And 8 Leaves A Remainder 3, But When ... What is the least number which when divided by 3,5,6,8,10,12 leaves a remainder of 2 in each case but when divided by 13 leaves no remainder see answers advertisement amanraj56. What is the smallest number which when divided by 3, 5, 6, 8, 10 and 12 leaves a remainder of 2 in each case but which when divided by 13 leaves no remainder? lcm of 3, 5, 6, 8, 10 and 12 is 120. (3x 2) is divisible by 13 if we put x = 1, 2, 3, 4, …… the answer is 962. > the bihar stet 2025 notification will be released soon. To find the least number that leaves a remainder of 2 when divided by 3, 5, 6, 8, 10, and 130, we can express the problem as finding a number n such that: n % 3 = 2, n % 5 = 2, n % 6 = 2, n % 8 = 2, n % 10 = 2, and n % 130 = 0. The correct answer is by option verification ,962 is divided by 3,5,6,8,10 and 12 leaves remainder 2, but when divided by 13 leaves no remainder (or)l.c.m of 3,5,6,8,10,12 is 12.

Solved 3. Find The Least Number Which When Divided By | Chegg.com

Solved 3. Find The Least Number Which When Divided By | Chegg.com To find the least number that leaves a remainder of 2 when divided by 3, 5, 6, 8, 10, and 130, we can express the problem as finding a number n such that: n % 3 = 2, n % 5 = 2, n % 6 = 2, n % 8 = 2, n % 10 = 2, and n % 130 = 0. The correct answer is by option verification ,962 is divided by 3,5,6,8,10 and 12 leaves remainder 2, but when divided by 13 leaves no remainder (or)l.c.m of 3,5,6,8,10,12 is 12. What is the least number which when divided by the number 3, 5, 6, 8, 10 and 12 leaves in each case a remainder 2 but when divided by 22 leaves no remainder ? a. 312. What is the smallest number which when divided by 3, 5, 6, 8, 10 and 12 leaves a remainder of 2 in each case but which when divided by 13 leaves no remainder? lcm of 3, 5, 6, 8, 10 and 12 is 120. (3x 2) is divisible by 13 if we put x = 1, 2, 3, 4, …… the answer is 962. What is the least number which when divided by the numbers 3, 5, 6, 8, 10 and 12 leaves in each case a remainder 2 but when divided by 13 leaves no remainder ? 312. First find the lcm of the numbers that the required number is divisible with, i.e., 3,5,6,8,10,12 which is 120. therefore the required number is of the form 120x 2 (since it leaves a reminder of 2) now the number is a multiple of 13. so 120x 2 is a multiple of 13. => 117x 3x 2 is a multiple of 13.

SOLVED: 18 Which List Shows The Numbers In Order From Least To Greatest? 3 3 5 4 2 Notice That ...

SOLVED: 18 Which List Shows The Numbers In Order From Least To Greatest? 3 3 5 4 2 Notice That ... What is the least number which when divided by the number 3, 5, 6, 8, 10 and 12 leaves in each case a remainder 2 but when divided by 22 leaves no remainder ? a. 312. What is the smallest number which when divided by 3, 5, 6, 8, 10 and 12 leaves a remainder of 2 in each case but which when divided by 13 leaves no remainder? lcm of 3, 5, 6, 8, 10 and 12 is 120. (3x 2) is divisible by 13 if we put x = 1, 2, 3, 4, …… the answer is 962. What is the least number which when divided by the numbers 3, 5, 6, 8, 10 and 12 leaves in each case a remainder 2 but when divided by 13 leaves no remainder ? 312. First find the lcm of the numbers that the required number is divisible with, i.e., 3,5,6,8,10,12 which is 120. therefore the required number is of the form 120x 2 (since it leaves a reminder of 2) now the number is a multiple of 13. so 120x 2 is a multiple of 13. => 117x 3x 2 is a multiple of 13.

What Is The Least 4 Digit Number When Divided By 3,4,5 And 6 Leaves Remainder 2 In Each Case ...

What Is The Least 4 Digit Number When Divided By 3,4,5 And 6 Leaves Remainder 2 In Each Case ... What is the least number which when divided by the numbers 3, 5, 6, 8, 10 and 12 leaves in each case a remainder 2 but when divided by 13 leaves no remainder ? 312. First find the lcm of the numbers that the required number is divisible with, i.e., 3,5,6,8,10,12 which is 120. therefore the required number is of the form 120x 2 (since it leaves a reminder of 2) now the number is a multiple of 13. so 120x 2 is a multiple of 13. => 117x 3x 2 is a multiple of 13.

What is the least number which when divided by the number 3,5,6,8, 10 and 12 leaves in each case a r